Change of sign method Essay Example for Free

Change of sign order EssayI use the same system to keep doing decimal research. to work out a more accurate firmness of purpose. Take increments in sizing 0. 1 within the interval 1. 5,1. 6 From the above we suffer see that must lie between 1. 52,1. 53. It can be very clear if I use graph. I ordain do a separate research this time by development the same method to prove my result is correct. Now I can find a more accurate result from the research which lies between 1. 521,. 1522. Here is a graph to prove the interval is right. However, I will take 4 decimal places to improve the trueness of the interval.Also I will use the same method again. As we can see the fundament is between 1. 5213,1. 5214 Same again. Autograph is used to prove my solution is right. Error bounds This is the process which tally how the accuracy of the roots are. From those 4 decimal search I have done so far, I can say that the answer is between 1. 5213 and 1. 5214. These can be improved the accura cy. Assume X=1. 5213 f(x)=(1. 5213)3-1. 5213-2=-0. 00047 X=1. 5214 f(x)=(1. 5214)3-1. 5214-2=0. 000121 Because the answer is -0. 0004700. 000121. So the answer must between 1. 5213 and 1.5214.However , these are not the exact answer so I have to portend them. In this case, X=1. 5213. 5, so the error bound is . Because this is the pith point between the interval. Fail example by using Exel It is not guaranteed to use this method, because at that place motionlessness has some problems in it. See the graph below As we can see the curl touches the x axis. The root lies between 0 and 1. I am going away to use Exel program to prove it. in that location is no change of sign of this equation. So we can say that the change of sign method is failed. Newton-Raphson methodThis is another fixed point estimation method, and as for the previous method it is necessary to use an estimate of the root as a starting point. The process can be repeated to give a sequence of points x2, x3 I am going to use the following equation. As we can see there are 2 roots in this function. The first root lies close to +1. But I will estimate the first root is x1 = +2. I will show it in graphical as +2 is a starting point. There is a technical way to do Newton-Raphson method by using Autograph. I will do it step by step with showing the graph.I click the curve thusly right click it and chook the Newton Raphson Iteration option. I have entered the value that I estimated, then press the right side button. The solutions appear automatically. The answer that I got is 1. 27202. Error bound Because my solution is 5. bp. So the answer will be x=1. 27202 The numbers that I squared shows how close to the real answer. So we can say there are some error in it. I am going to try another root of the equation. I have estimated the x1 = -2. As I can see from the graph, -1. 27202 is the take up answer I can get. Then I will check whether the solutions are correct.